Suppose

U={(x,x,y,y)F4:x,yF}U = \{(x,x,y,y) \in \mathbf{F}^4 : x,y \in \mathbf{F}\}

Find a subspace WW of F4\mathbf F^4 such that F4=UW\mathbf F^4 = U \oplus W.


Let

W={(z,0,t,0)F4:z,tF}W = \{(z,0,t,0) \in \mathbf{F}^4 : z,t \in \mathbf{F}\}

To see it's a direct sum we use 1.44, suppose u+w=0u + w = 0 then

(x+z,x,y+t,y)=0(x+z,x,y+t,y) = 0

Since each coordinate must be zero this implies x=y=0x=y=0, plugging that back in we see z=t=0z=t=0 as well. Thus UW={0}U \cap W = \{0\} so by 1.44 it's a direct sum.

To see U+W=F4U + W = \mathbf F^4 is straightforward, just write an element of F4\mathbf F^4 in terms of its coordinates then solve for x,y,z,tx,y,z,t.