Suppose
U={(x,x,y,y)∈F4:x,y∈F}
Find a subspace W of F4 such that F4=U⊕W.
Let
W={(z,0,t,0)∈F4:z,t∈F}
To see it's a direct sum we use 1.44, suppose u+w=0 then
(x+z,x,y+t,y)=0
Since each coordinate must be zero this implies x=y=0, plugging that back in we see z=t=0 as well. Thus U∩W={0} so by 1.44 it's a direct sum.
To see U+W=F4 is straightforward, just write an element of F4 in terms of its coordinates then solve for x,y,z,t.