Find a number t such that
(3,1,4),(2,−3,5),(5,9,t)
Is not linearly independent in R3
We want (for some ak=0)
a1(3,1,4)+a2(2,−3,5)+a3(5,9,t)=0
If some ak=0, we must have a3=0 since (3,1,4) and (2,−3,5) are linearly independent. Therefor we can divide by a3, relabel and rearrange to get
(5,9,t)=b1(3,1,4)+b2(2,−3,5)
We'll pick b1,b2 to satisfy the first two constraints (the first coordinates must be equal) then pick t to satisfy the last one.
{5=3b1+2b29=1b1−3b2⟹b1=3,b2=−2
Which gives t=3(4)−2(5)=2, which is our solution since
−1(5,9,2)+3(3,1,4)−2(2,−3,5)=0
Implying they are linearly dependent.
(I could have skipped the derivation and jumped to this part, but that makes it harder to understand)