Suppose UU and WW are both 4-dimensional subspaces of C6\mathbf C^6. Prove that there exist two vectors in UWU \cap W such that neither of these vectors is a scalar multiple of the other.


By 2.43

dim(UW)=dimU+dimWdim(U+W)=8dim(U+W)2\begin{aligned} \dim(U \cap W) &= \dim U + \dim W - \dim(U+W) \\ &= 8 - \dim(U + W) \\ &\ge 2 \end{aligned}

Therefor we can find two independent vectors v1,v2UWv_1,v_2 \in U \cap W which clearly won't be scalar multiples of eachother.