Prove that there does not exist a linear map from F5 to F2 whose null space equals
{(x1,x2,x3,x4,x5)∈F5:x1=3x2 and x3=x4=x5}
This nullspace has dimension 2, since we can pick x1,x3 to determine the others. 3.22 implies dimrange T=3, but range T⊆F2 so it can't have bigger dimension! (see 2.38). Therefor T cannot exist