Suppose v1,v2,v3,v4v_1,v_2,v_3,v_4 is a basis of VV. Prove that

v1+v2,v2+v3,v3+v4,v4v_1+v_2,v_2+v_3,v_3+v_4,v_4

Is also a basis of VV.


This is literally 2a/6. spanning is obvious and linear independence is a compuation covered in 2a/6.